“Anything that can be written in Rust will eventually be written in Rust”
Someone has to explain how rm, which doesn’t allocate any memory (as far as I can tell), isn’t memory safe ?
If I cant remember what dir I’m in, then rm is mot very memory safe is it?
[edit: spelling]
I don’t know whether rm is memory-safe or not, but vpr is. By ‘memory-safe alternative’ I meant that this alternative is memory-safe, but not that rm isn’t.
Reminds me of when they started printing “vegan” and “gluten free” on water bottles.
In GNU coreutils the implementation of rm doesn’t allocate memory however I believe alternative implementations do.
Here’s an example from the OpenBSD source code - https://github.com/openbsd/src/blob/222e275fb89ffb67abe0726dee2b107220092dc3/bin/rm/rm.c#L335
Presumably other *BSDs use something similar? Didn’t check out FreeBSD or anything.
Edit: So I suppose if you are using a BSD-type system (maybe including macOS?), and memory safety was important to you (to the point of extreme paranoia), then you might want to look into this rust project. Or just use the GNU implementation.
