Is this the best way to use expectEqual?
fn add(a: i64, b: i64) i64 {
return a + b;
}
test "basic test" {
try std.testing.expectEqual(@as(i64, 10), add(3, 7));
}
Without the @as the test doesn’t even compile:
./src/main.zig:12:40: error: expected type 'comptime_int', found 'i64'
try std.testing.expectEqual(10, add(3, 7));
Having to use @as seems makes the test less readable. It seems to me inferring the type of expected from the type of actual would make more sense.
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1 point
Should work if “10” is also declared as a variable with type “i64” I think?
0 points
Sure, you could do:
const ten: i64 = 10;
try std.testing.expectEqual(ten, add(3, 7));
Is there a way to write an i64 literal?
2 points
If we look at the signature expectEqual(expected: anytype, actual: @TypeOf(expected)) !void, notice that the second arg’s type depends on the first arg’s type.
To avoid using @as coercion, we can just swap the passing arguments. comptime_int can be inferred as i64, not the other way around. And that makes sense because literal values are unsized.