Welcome everyone to the 2023 advent of code! Thank you all for stopping by and participating in it in programming.dev whether youre new to the event or doing it again.

This is an unofficial community for the event as no official spot exists on lemmy but ill be running it as best I can with Sigmatics modding as well. Ill be running a solution megathread every day where you can share solutions with other participants to compare your answers and to see the things other people come up with


Day 1: Trebuchet?!


Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • Code block support is not fully rolled out yet but likely will be in the middle of the event. Try to share solutions as both code blocks and using something such as https://topaz.github.io/paste/ or pastebin (code blocks to future proof it for when 0.19 comes out and since code blocks currently function in some apps and some instances as well if they are running a 0.19 beta)

FAQ


πŸ”’This post will be unlocked when there is a decent amount of submissions on the leaderboard to avoid cheating for top spots

πŸ”“ Edit: Post has been unlocked after 6 minutes

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4 points

[Rust] 11157/6740

use std::fs;

const m: [(&str, u32); 10] = [
    ("zero", 0),
    ("one", 1),
    ("two", 2),
    ("three", 3),
    ("four", 4),
    ("five", 5),
    ("six", 6),
    ("seven", 7),
    ("eight", 8),
    ("nine", 9)
];

fn main() {
    let s = fs::read_to_string("data/input.txt").unwrap();

    let mut u = 0;

    for l in s.lines() {
        let mut h = l.chars();
        let mut f = 0;
        let mut a = 0;

        for n in 0..l.len() {
            let u = h.next().unwrap();

            match u.is_numeric() {
                true => {
                    let v = u.to_digit(10).unwrap();
                    if f == 0 {
                        f = v;
                    }
                    a = v;
                },
                _ => {
                    for (t, v) in m {
                        if l[n..].starts_with(t) {
                            if f == 0 {
                                f = v;
                            }
                            a = v;
                        }
                    }
                },
            }
        }

        u += f * 10 + a;
    }

    println!("Sum: {}", u);
}

Link

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2 points

Oh, doing this is Rust is really simple.

I tried doing the same thing in Rust, but ended up doing it in Python instead.

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1 point

Ive been trying to learn rust for like a month now and I figured I’d try aoc with rust instead of typescript. Your solution is way better than mine and also pretty incomprehensible to me lol. I suck at rust -_-

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1 point
*

In case that this might help.

h.chars() returns an iterator of characters. Then he concatenate chars and see if it’s a digit or a number string.

You can swap match u.is_numeric() with if u.is_numeric and covert _ => branch to else.

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3 points

he used one letter variable names, it’s very incomprehensible.

Get yourself thru the book and you’ll get everything here.

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1 point

Yeah tried to golf it a bit so its not very readable

Seems like the site doesn’t track characters though so won’t do that for future days

It basically just loops through every character on a line, if it’s a number it sets last to that and if its not a number it checks if theres a substring starting on that point that equals one of the 10 strings that are numbers

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2 points

Started a bit late due to setting up the thread and monitoring the leaderboard to open it up but still got it decently quick for having barely touched rust

Probably able to get it down shorter so might revisit it

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Advent Of Code

!advent_of_code@programming.dev

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An unofficial home for the advent of code community on programming.dev!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2023

Solution Threads

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