The game says this hand is 1 tile away from tenpai but I just don’t see it.
Discard 8pin now, draw 7sou and discard 5pin, you’re tenpai waiting on 5sou
Holy shit you’re right. Now I see it, thanks. Was it easy for you to see? Let me know if you have tips. I always look for 5 blocks, but here those that I saw were 333pin, 566pin, 23sou, 44sou and 668sou…
Idk I also just applied 5 block method but came to a different conclusion than you. 333pin, 5668pin (expecting 2), 234sou, 4668sou (expecting 2). I gave the solution that reduces 5668pin group to one block because that’s what the game is suggesting, but you can do the same with the sous instead by discarding 8sou now, draw 7pin and discard 4sou, now tenpai waiting on 4/7pin
I don’t see why you split 234sou because that’s literally already complete, I wouldn’t even consider using 4sou as the head unless I draw another 4sou or I draw 1sou, even then I’d discard 1sou to preserve tanyao especially when there are other head candidates in the hand already
Thanks to your explanation I see my issue now. To find my 5 blocks I prioritize open waits, so I tend to see those kinds of 4 tiles shapes as 1 block + 1 useless tile. But if in the process I had to split a completed block into 1 open wait + 1 pair, my shanten goes back…
Splitting a completed block this way is very useful when I don’t have a pair yet, because the pair itself is a completed block so I essentially get a free open wait. But in this case I already had plenty of pairs so I just split a completed block into 2 uncompleted blocks, which I should do only when my hand doesn’t even have 5 blocks to begin with
